PartA A proton moves in the magnetic field B0.60i T with a speed of 1.1x107 m/s
ID: 776720 • Letter: P
Question
PartA A proton moves in the magnetic field B0.60i T with a speed of 1.1x107 m/s in the directions shown in the figure (Figure 1) In Figure (a), what is the magnetic force F on the proton? Give your answers in component form. Express vector F in the form of Fz, Fy, F , where the , y, and components are separated by commas. You may want to review (Pages 815- 820) Submit Request Answer Part B In Figure (b), what is the magnetic force F on the proton? Give your answers in component form. Express vector F in the form of F·P,, F, , where the z, y, and z components are separated by commas. Figure 1 of 1 Submit Request Answer (a) Z_ (b) Z Provide FeedbackExplanation / Answer
a) F = q V B sin theta
= 1.6 * 10-19 * 1.1 * 107 * 0.60 * sin 45
F = ( 7.47 * 10-13 N ) j
b) F = q V B sin 270
= 1.6 * 10-19 * 1.1 * 107 * 0.60 * sin 180
F = 0 N [there is no magnetic force on proton]