ID: A st2 W18 Multiple Choice A flat coil of wire consisting of 20 turns, each w
ID: 776796 • Letter: I
Question
ID: A st2 W18 Multiple Choice A flat coil of wire consisting of 20 turns, each with an area of 50 cm, is positioned perpendicularly to a unlform magnetic field that has a total resistance of 040 , what is the magnitude of the induced current? a 1.40 A b. 1.00 A c. 0.50 A 1. its magnitude at a constant rate from 2.0 T to 6.0 T in 1.0 s. If the coil d. 1.60 A e. 0.30 A 2. A current may be induced in a coil by moving one end of a bar magnet through the coil. b. moving the coil toward one end of the bar magnet. c a bolding the coll near a second coil while the electric current in the second coil is increasing all of the above. d. e none of the above. In the arrangement shown, a conducting bar of negligible resistance slides along horizontal, parallel, fricti conducting rails connected as shown to a 2.0 resistor. A uniform 1.5-T magnetic field is plane of the paper. If E 60 cm, at what rate is thermal energy being generated in the resistor at the insta 3. speed of the bar is equal to 5.0 m/si b. 9.3 W d. 10.1 Ww e 18.2 wExplanation / Answer
1. Induced emf = n*(BfAf-BiAi)*A / t = n*(Bf-Bi)*A/t = (6-2)*20*(50/10000m^2) / 1s = 0.4 V
So,induced current = Induced emf / resistance = 0.4/ 0.4
So,induced current = (b) 1A
2. Current may be induced in a coil by by (d) all of the above ; which are (a) moving bar magnet through the coil, (b) moving coil toward end of bar magnet, (c) holding coil near secondary coil, with current in secondary coil increasing
3. induced emf= B*(Af-Ai) / t = 1.5*0.6*5 = 4.5 V
Now, heat energy = V^2/ R = 4.5^2/ 2
So, rate of thermal energy being generated is (d) 10.1W
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