Problem 5 An RC circuit, hooked up to a battery as shown in the figure below, st
ID: 777240 • Letter: P
Question
Problem 5 An RC circuit, hooked up to a battery as shown in the figure below, starts with an uncharged capacitor The resistance in the circuit is R 690 the capacitor has capacitance C a) What is the time constant for this circuit? 5 and the battery man ans the em o 340 V The switch s sed at ime 000 san the apa itor begins an e. Submit Answer Tries 0/6 b) What is the charge on the capacitor after the switch has been closed for t 4.29x102 seconds? Submit Answer Tries 0/6 c) What is the current through the circuit after the switch has been closed for t-4.29x102 seconds? Submi't Answer Tries 0/6 d) What is the voltage across the capacitor after the switch has been closed for t= 4.29×10-seconds ? Submit Answer Tries 0/6Explanation / Answer
Given R = 690 ohm, C = 51 muF, E = 34 V
(a) Time constant Tau(t) = R*C = 690*51 = 35190 micro sec
(b) Q(t) = Qo [ 1 - e-t/ ] ;
where, Qo = CV = 51*34 = 1734 micro coulmb:
now, Q(t) = 1734*(1 - e-(0.0429/0.035190)) = 1221.6 micro coulmb
(c) I(t) = (V/R) e-t/ = Io e-t/ = (34/690)*e-(0.0429/0.035190)) = 0.0145 A
(d) V(t) = Vo [ 1 - e-t/ ]
= 34*(1 - e-(0.0429/0.035190))
= 32.99 V