Class M l Help Homework #6 Begin Date: 352018 1201 00 AM-Due Date: 3 182018 il 5

Question

Class M l Help Homework #6 Begin Date: 352018 1201 00 AM-Due Date: 3 182018 il 59 00 PM End Date: 3 a7%) Problem 5: Consider the creut diagram depocted in the figure. 18 12:01:00 AM E1-18V 0.5 250 50% Part (a) What equation do you get when you apply 0-66+1 R R-IR2 the loop rule to the loop abodefgha, in terms of the variables in the figure? Grade Summary Late Work 96 Lat, Potential S0% 12 3 Atespts remaning ACKSPACECLEAR Feedback Hints:deduction per hi Hstsraining Feedback: 1 foradeductio Ss Part (b) if the cusres through the top branch ia Atthe curent through the bottops FII F12

Explanation / Answer

After appling the KVL in the loop "abcdefgha" -

For this we have to start from point a to the direction of I2 than-

-I2R2 + E1 - I2f1 + I3R3 + I3f2 - E2 = 0 (Answer)

You haven't mention the term "I3f2 " in your answer.

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