Consider 2.00 moles of Argon, considered an Ideal Gas, at a density of 5.00 g/L
ID: 782991 • Letter: C
Question
Consider 2.00 moles of Argon, considered an Ideal Gas, at a density of 5.00 g/L and a pressure of 2.00 atm. What is the closest value to the temperature of this gas?
195 K
I think I am doing something wrong since I am using the PV=nRT equation, so
2.00 atm (5.00g/L)=2.00(.08206)T so
10= (.16142)T
10/.16142 = 61.9 so the closest answer is 61 K.
However it says the answer is wrong, someone please help!
A. 298 K B. 137 K C. 61 K D. 273 K E.195 K
I think I am doing something wrong since I am using the PV=nRT equation, so
2.00 atm (5.00g/L)=2.00(.08206)T so
10= (.16142)T
10/.16142 = 61.9 so the closest answer is 61 K.
However it says the answer is wrong, someone please help!
Explanation / Answer
B. 137 K