Given that the molar mass of H 3 PO 4 is 97.994 grams, determine the number of g

Question

Given that the molar mass of H3PO4 is 97.994 grams, determine the number of grams of H3PO4 needed to prepare 0.25L of a 0.2M H3PO4 solution. Show your work.
What volume, in Liters, of a 0.2 M H3PO4 solution can be prepared by diluting 50 mL of a 5M H3PO4 solution?
Given that the molar mass of H3PO4 is 97.994 grams, determine the number of grams of H3PO4 needed to prepare 0.25L of a 0.2M H3PO4 solution. Show your work.
What volume, in Liters, of a 0.2 M H3PO4 solution can be prepared by diluting 50 mL of a 5M H3PO4 solution?

Explanation / Answer

Here

No. of Moles = MV

= 0.25*0.2

= 0.05 moles

So

Mass = 97.994*0.05

= 4.8997 g

M1V1 = M2V2

Therefore

V*0.2 = 50*10^-3*5

V = 1.25 L

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