Which one of the following equations correctly represents alpha decay of 222 86

Question

Which one of the following equations correctly represents alpha decay of 22286Rn? Answer                                                   a.            22286Rn  ?     22287Fr  +  0-1                             b.            22286Rn  +  42He  ?     22688Rn                             c.            22286Rn   ?  21884Po  +  42He                             d.            22286Rn   ?  22082Po  +  42He                             e.            22286Rn  ?     22285At  +  01 Which one of the following equations correctly represents alpha decay of 22286Rn? Which one of the following equations correctly represents alpha decay of 22286Rn? 22286Rn  ?     22287Fr  +  0-1 22286Rn  +  42He  ?     22688Rn 22286Rn   ?  21884Po  +  42He 22286Rn   ?  22082Po  +  42He 22286Rn  ?     22285At  +  01                             a.            22286Rn  ?     22287Fr  +  0-1                             b.            22286Rn  +  42He  ?     22688Rn                             c.            22286Rn   ?  21884Po  +  42He                             d.            22286Rn   ?  22082Po  +  42He                             e.            22286Rn  ?     22285At  +  01

Explanation / Answer

Answer is C.

Radon with atomic number 86 and mass number 222 emits an alpha particle(decay) which is 2He4 also an helium particle and forms Polonium isotope with atomic number 84 and mass number 218.

It satisfies both left and right hand side equations hence they are balanced other equations do not emit alpha or unblanced.

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