I will give full points for anyone that shows proper work ! Consider the electro

Question

I will give full points for anyone that shows proper work !

Consider the electronic transition from n = 2 to n = 4 in a hydrogen atom and select the correct statement below.

. A photon of 206 nm wavelength and 9.66x10-32 J energy was emitted from the hydrogen atom during this electronic transition. B. A photon of 486 nm wavelength and 4.09x10-19 J energy was emitted from the hydrogen atom during this electronic transition. C. A photon of 206 nm wavelength and 9.66x10-32 J energy was absorbed by the hydrogen atom during this electronic transition. D. A photon of 486 nm wavelength and 4.09x10-19 J energy was absorbed by the hydrogen atom during this electronic transition.

Explanation / Answer

delta e = E final - E initial
final energy = 4
initial energy = 2
energy in a hydrogen atom = -2.178 x 10^-18 j
use this equation
E= -2.178 x 10^-18 j (z^2/n^2)
z= number of electrons
E=-2.178 x 10^-18(1^2/4^2)-(-2.178 x 10^-18 j)(1^2/2^2)

B) is correct

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