CaC 2 + 2 H 2 O = C 2 H 2 + Ca(OH) 2 Part A) If 40 g of calcium carbide (CaC2) r

Question

CaC2 + 2 H2O = C2H2 + Ca(OH)2

Part A) If 40 g of calcium carbide (CaC2) reacts with 25.0 g of water, how many liters of acetylene (C2H2) can be produced, assuming the reaction goes to completion at 60 degrees F and 763 mmHg?  

Part B) If calcium carbide has a standard enthalpy of formation of -59.8 kj/mol and acetylene has a standard enthalpy of formation of 226.73 kj/mol, what is the standard enthalpy change for the reaction?

Part C) Is the reaction endothermic or exothermic? Why??

Please explain how to get to the answers, thank you!  

Explanation / Answer

1 mole of CaC2 needs 2 moles of H2O

we have 40/(40 + 24) = 40/64 moles of CaC2 = 5/8 moles of CaC2

So we need H2O = 5/4 moles for complete reaction = 1.25 moles

Moles of Water = 25/18 = 1.388 moles are present

Hence CaC2 is the limiting reagent

1 mole of CaC2 produces 1 mole of C2H2

5/8 mole of CaC2 will produce = 5/8 mole of C2H2

Hence liters of acetylene produce = 5/8 * 22.4 = 14 L of C2H2

b) Standard enthalpy of reaction = 226.73 + 59.8 kJ/mole = 286.53 kJ/mole

c) its an endothermic reaction as standard enthalpy change for the reaction is positive.

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