For those mixtures that are not at equilibrium, will the reaction go in the forw

Question

For those mixtures that are not at equilibrium, will the reaction go in the forward or reverse direction to reach equilibrium? (1) will go in the reverse direction and (3) will go in the forward direction (1) and (3) will go in the reverse direction (1) and (3) will go in the forward direction (1) will go in the forward direction and (3) will go in the reverse direction The reaction has an equilibrium constant Kc = 1/3. The following pictures represent reaction mixtures that contain A atoms (red), B atoms (blue), and A2 and AB molecules: Which reaction mixture is at equilibrium? mixture (3) mixture (2) mixture (1)

Explanation / Answer

Q1. Both 1 and 3 will go in the reverse direction towards the reactants

Formula used for Qc:

Qc1=[3x5]/[1x1]=15

Qc2=[1x3]/[3x3]=1/3

Qc3=[2x4]/[2x2]=2

For Qc>Kc=too much product

For Qc=Kc=equilibrium

For Qc<Kc=too much reactants

Q2. Mixture 2

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