Question
ALL I NEED ARE THE LAST TWO PARTS, MUST ANSWER BOTH CORRECTLY FOR 5 STARS
A 0.90 A mu L sample of an equal volume mixture of 2-pentanone and 1-nitropropane is injected into a gas chromatograph. The densities of these compounds are 0.8124 g/mL for 2-pentanone and 1.0221 g/mL for 1-nitropropane. What mass of each compound was injected? Mass of 2-pentanone Mass of 1-nitropropane = The peak areas produced on this injection were 1636 units for 2-pentanone and 1276 units for 1-nitropropane. Calculate the response factor for each compound as area per mg. 2-pentanone: An unknown mixture of these two components produces peak areas of 1593 units (2-pentanone) and 1111 units (1-nitropropane).
Explanation / Answer
How did you solve for those percentages?
And how do you calculate the response factor for each compound as area per mg?