Complete the following table by calculating the missing entries. In each case in
ID: 796147 • Letter: C
Question
Complete the following table by calculating the missing entries. In each case indicate whether the solution is acidic or basic
. Complete the first row.[OH-]
Complete the first row.[PH]
Complete the first row.[POH]
Complete the first row. Indicate whether the solution is acidic or basic.
Complete the second row.[H+]
Complete the second row.[PH]
Complete the second row.[POH]
Complete the second row. Indicate whether the solution is acidic or basic.
Complete the third row.[H+]
Complete the third row.[OH-]
Complete the third row.[PoH
Complete the third row. Indicate whether the solution is acidic or basic.
Complete the fourth row.[H+]
Complete the fourth row.[OH-]
Complete the fourth row.[PH
]Complete the fourth row. Indicate whether the solution is acidic or basic.
[H+] [OH?] pH pOH Acidic or basic? 7.7Explanation / Answer
First Row ;
Given [H+] = 7.7 x 10-3 M
we know that [H+] [ OH-] = 10- 14
so [OH-] = 10-14/ 7.7 x 10-3
[OH-] = 1.2987 x 10-12 M
pH= -log [H+]
=-log 7.7 x 10-3
=2.1135
pH+ pOH =14
pOh=14-pH
=14-2.1135
pOH = 11.886
the solution is acidic as pH < 7
Second Row ;
given [OH-] = 3.9 x 10-10 M
[H+] = 10-14/3.9 x 10-10
[H+] = 2.564 x 10-5 M
pH=-log [H+]
=-log 2.564 x 10-5
=4.59
pH=4.59
pOH = 14-4.59
pOH = 9.41
the solution is acidic as pH<7
Third Row :
Given pH= 8.26
The solution is basic as pH > 7
So pOH = 14- 8.26
pOH= 5.74
pOh= -log [OH-]
5.74 = -log [OH-]
[OH-] = 1.82 x 10-6
so [H+] = 10-14/1.82 x 10-6
[H+] = 0.55 x 10-8 M
Fourth Row :
Given pOh=5.73
pH=14-5.73
pH= 8.27
So the solution is basic as pH > 7
pOH = -log [OH-]
5.73 = -log [OH-]
[OH-] = 1.86 x 10-6 M
[H+] = 10-14/1.86 x 10-6
[H+] = 0.54 x 10-8 M