Please explain how each one is done! thanks. Consider the reversible reaction 2A

Question

Please explain how each one is done! thanks.

Consider the reversible reaction 2A 3B. What is the value of the equilibrium constant if the equilibrium concentration of A is 0.124 M and the equilibrium concentration of B is 0.327 M? 2.27 0.440 2.64 21.3 4.05 x 10 -2 How much heat is required when 3.00 g of benzene vapor evaporates at its boiling point? Note: the boiling point for benzene is 80.1 degree C. (See the front of the exam for useful information about benzene.) 384J 420. J 1190 J 9.26 J 672 J

Explanation / Answer

1)Keq=[B]^3/[A]^2

=(0.327)^3/(0.124)^2

=2.274 M

A is the correct option

2)latent heat of vapourization of benzene is 30.73 KJ/mol

3 g=3/78 moles

So heat required=30.73x1000x3/78

=1190 J

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