Question
Please Help me with this multiple choice questions, i would appreciate it
The rate constant, k1, for the forward reaction is: higher than the rate constant for the corresponding reverse reaction, k.1 the same as the rate constant for the corresponding reverse reaction, k.1 lower than the rate constant for the corresponding reverse reaction, k.1 without an exact value for Keq it is impossible to tell k1 and k-1 are not related to one another Adding a strong acid such as HCIO4 would do the following to the above equilibrium: increase the K0 (acid dissociation constant) of H2SO4 decrease the K0 of H2SO4 not affect the Ka of H2SO4 it's impossible to tell without trying it and measuring none of these answers is correct If H2SO4 were purple in solution, adding HCIO4 (colourless) to the above equilibrium would: make the solution more purple make the solution less purple not change the colour of the solution make the solution cloudy none of the above At equilibrium which of the following processes is happening faster? HSO-4 + H- rightarrow H2SO4 (because Ka is so high) H2SO4 rightarrow HSO4- + H+ (because Ka is so high) both a and b are happening at the same rate it's impossible to tell none of the above answers are correct
Explanation / Answer
6)e
7)c
8)e
9)c
10)a