The rate law for the reaction 2NO(g) + Br 2 (g) ? 2NOBr(g) is rate = k[NO] 2 [Br
ID: 799273 • Letter: T
Question
The rate law for the reaction2NO(g) + Br2(g) ? 2NOBr(g)
is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? possible answers but please show work and explain: The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The rate law for the reaction
2NO(g) + Br2(g) ? 2NOBr(g)
is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? The rate law for the reaction
2NO(g) + Br2(g) ? 2NOBr(g)
is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change.
Explanation / Answer
rate is directional propotional to squere of concentration of NO so if the concentration of NO was doubled then rate will increase by factor of 4