Question #1 (5pts): Consider your ln(rate) vs. 1000/T graph. Was the data evenly
ID: 811005 • Letter: Q
Question
Question #1 (5pts): Consider your ln(rate) vs. 1000/T graph. Was the data evenly distributed around the line or does the low (or high) temperature end of the curve have more scatter than the other? Is this result consistent with your observations? Explain. Question #2 (5pts): The introduction stated that often the rate doubles for each temperature increase of 10 degree C. What value of the activation energy would cause the rate to double between 25 and 35 degree C? Question #3 (2.5pts): In this experiment you used a yellow colorimetric guide to establish the end of the reaction. Would you expect to get the same value of the activation energy if red was chosen rather than yellow? Support your answer with your observations of the reaction.Explanation / Answer
1. Yes. The data are scattered in the high temperature region. This may be due to the inaccuracy in making measurements at high temperatures.
2. K = A*exp{-Ea/RT}
ln K = lnA - Ea/RT, let K = K1 at 298K and K = 2K1 at 308K.
then, ln2 = (Ea/8.314)*(1/298 - 1/308)
so, Ea = 52.894kJ/mol
3. Activation energy is of a reaction depends on the reactants. If an indicator used that gives off red colour instead of yellow, it means that the indicator is interacting with reactant differently and hence one can expect a different Ea.