Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

I will award full points to complete answers with work!!! Analysis of an Aluminu

ID: 814184 • Letter: I

Question

I will award full points to complete answers with work!!!

Analysis of an Aluminum-Zinc Alloy

Data:

mass of gelatin capsule: 0.115 g

mass of alloy sample plus capsule: 0.265 g

mass of empty beaker: 250.3 g

mass of beaker plus displaced water: 343.8 g

Barometric pressure: 765.0 mm Hg

temperature: 15.3 degrees Celcius

Calculations:

Mass of alloy sample: 0.150 g

Mass of displaced water: 93.5 g

A. volume of displaced water: ________mL

B. Volume of H2, (V)_________L

C. temperature of H2, (T) _________K

D. Vapor pressure of water at T, (VP H20)_______mm Hg

E. Pressure of dry H2, (P H2)_________mm Hg

F. Moles H2 from sample, (n H2) ____________moles

G. Moles H2 per gram of sample (N H2) _______moles/g

H. % Aluminum _________%

Explanation / Answer

A. volume of displaced water: ________mL

mass of displaced water = 93.5g

volume = mass/ density = 93.5g/ 1g/mL = 93.5mL

B. Volume of H2O, (V)_________L

volume = 93.5mL = 93.5mL/1000 =0.0935L

C. temperature of H2O, (T) _________K

Temperature = 15.3oC = 15.3 + 273.15 = 288.45K

D. Vapor pressure of water at T, (VP H20)_______mm Hg

PV = nRT

n = 93.5/18 = 5.2 moles

R =

T = 288.45 K

V = 0.0935L

P = nRT/V = (5.2 x 0.082 x 288.45 ) / 0.0935 = 1314.05atm = 1314.05 x 760 = 9.9E5 mmHg