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I will award points if you can help me get headed in the right direction for the

ID: 815838 • Letter: I

Question

I will award points if you can help me get headed in the right direction for the answer. Show the setup, I can do calculations. PLEASE help me...I have no idea how to do this problem.

2H2S (g) + SO2 (g)--> 3S (s) + 2H2O (g)

the facility is shown in Figure 1 on page 2. Due to the difficulty (and cost) of achieving high purity, the input streams (F1 and F2) both contain significant concentrations of CO2. The input feeds (F1 and F2) are blended to achieve a stoichiometric ratio of H2S and SO2 and are subsequently combined with a recycle stream and fed into the reactor. The solid sulfur is completely removed in the solids separator while the water is completely removed in a condenser. The stream leaving the condenser splits into a purge stream and the recycle stream. The flow rate in F1 is 100 mol/sec and the process achieves a 95% conversion of H2S. In addition, the recycle to feed ratio is R/f0=15

1) What are the flow rates of the recycle stream (R), solid sulfur stream (S), and water from the condenser (W)? This is ONE question....Please help

2H2S (g) + SO2 (g)--> 3S (s) + 2H2O (g) the facility is shown in Figure 1 on page 2. Due to the difficulty (and cost) of achieving high purity, the input streams (F1 and F2) both contain significant concentrations of CO2. The input feeds (F1 and F2) are blended to achieve a stoichiometric ratio of H2S and SO2 and are subsequently combined with a recycle stream and fed into the reactor. The solid sulfur is completely removed in the solids separator while the water is completely removed in a condenser. The stream leaving the condenser splits into a purge stream and the recycle stream. The flow rate in F1 is 100 mol/sec and the process achieves a 95% conversion of H2S. In addition, the recycle to feed ratio is R/f0=15 1) What are the flow rates of the recycle stream (R), solid sulfur stream (S), and water from the condenser (W)? This is ONE question....Please help

Explanation / Answer

F1 is given as 100 mol/sec. => amount of H2S in one sec = 0.90*100 = 90 mol

F2 should contain stoichiometric quantity of SO2. Therefore, F2 = (90/2)/0.95 = 47.4 mol

F0 = F1 + F2 = 100 + 47.4 = 147.4 mol/sec

Given that R/Fo = 15, R = 2211 mol/sec.

In the reactor, 95% H2S is converted. Therefore, amount of S is 0.95*(90/2)*3 = 128.25 mol/sec

amount of water in the condensor is 0.95*(90/2)*2= 85.5 mol/sec