I really do not understand how to calculate the last two problems. The concentra

Question

I really do not understand how to calculate the last two problems. The concentration of NaOH used was 0.1041 M, but I do not know which volume to use to calculate the moles, so therefore I cannot calculate molarity.

PART 2

Please indicate the concentration of each substance (acetic acid, n-propyl alcohol, n-propyl acetate, and water) in the initial mixture AND equilibrium mixture.

EXPERIMENT 31 Chemical Equilibrium 1: Titrimetric Determination of an Constant Results/Observations Concentration of standard NaOH solution Volume of NaOH to titrate 1 mL initial uncatalyzed mixture (first week) Concentration of acetic acid, M, in original mixture Volume of NaOH to titrate 1 mL catalyzed reaction mixture (first week Volume correction for sulfuric acid (to be applied next week) Volume of NaOH to titrate 1 mL of equilibrium mixture (second week) Volume (corrected) of NaOH to titrate acetic acid in equilibrium mixture Concentration of acetic acid, in reaching equilibrium mixture Change in concentration of acetic acid in reaching equilibrium

Explanation / Answer

For sample 1

use M1V1 for acetic acid= M2V2 for NaOH

M1= conc of acetic acid = 8.2M

V1 for acetic acid = unknown

M2 = 0.1041M

V2 = 23.07mL

So, 8.2M x V1 = 0.1041M x 23.07mL

V1 = 0.2929mL

Use this volume to calculate molarity.

Similarly, for sample 2:

M1= conc of acetic acid = 8.2M

V1 for acetic acid = unknown

M2 = 0.1041M

V2 = 23.41mL

So, 8.2M x V1 = 0.1041M x 23.41mL

V1 = 0.2971mL.

These volumes are needed to be used.

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