A 20.0 m L sample of 0.200 M H B r solution is titrated with 0.200 M N a O H sol

Question

A 20.0 mL sample of 0.200 MHBr solution is titrated with 0.200 MNaOH solution. Calculate the pH of the solution after the following volumes of base have been added.

Part 1 20.2mL Express your answer using two decimal places.

Part 2 36.0mL Express your answer using two decimal places.
Show all work please!

A 20.0 mL sample of 0.200 MHBr solution is titrated with 0.200 MNaOH solution. Calculate the pH of the solution after the following volumes of base have been added.

Part 1 20.2mL Express your answer using two decimal places.

Part 2 36.0mL Express your answer using two decimal places.
Show all work please!

Part 1 20.2mL Express your answer using two decimal places.

Part 2 36.0mL Express your answer using two decimal places.
Show all work please!
Part 2 36.0mL Express your answer using two decimal places.

Explanation / Answer

sorry i made small mistake

for 36.0mL

Moles HBr = 0.020 L x 0.200 M =0.0040
Moles NaOH = 0.036 L x 0.200 =0.0072

Moles 0H+ in excess = 0.0072-0.0040=0.0032
total volume = 0.056 L
conc. 0H+ = 0.0032 / 0.056 =0.057142
p0H =-log[oh-]=-log[0.057142]=1.24

pH=14-1.24=12.756

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