I have to do the Synthesis of Benzoic Acid reacted with carbon dioxide to get Be

Question

I have to do the Synthesis of Benzoic Acid reacted with carbon dioxide to get Benzoic Acid. I am unsure how to calculate the theoretical yield of Benzoic acid and it gave a hint that i would have to first determine the limiting reagent out of the 3 possible reagents, bromobenzene, magnesium metal and dry ice (CO2).

0.24g magnesium turnings (MM=24.31g/mol)

1 mL bromobenzene (MM=157.02g/mol)(D=1.491g/mL)

5g crushed dry ice (MM=44.01g/mol)

There are other things used in the experiment but i did not include them because it only said it could be those 3.

I understand all other points of the lab but i always get stuck trying to figure this out!

Thank you!

Explanation / Answer

Limiting Reagent (starting material present in fewest number of moles):

.24g/24.31= 0.00987

1ml(1.491g/ml)(mol/157.02g)= 0.014158

5g/44.01g = 0.1136

* so LR is magnesium turnings *

Theoretical yield (g) = (moles magnesium turnings)( # moles benzoic acid / # moles magnesium turnings)(MM of benzoic acid)

PS: I was not sure what the mole to mole ratio of the LR and benzoic acid were in your balanced chemical reaction... but you can get that from balanced chemical equation if you have it.

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