Can someone help me with this? I\'m stuck on the calculations :( I appreciate th

Question

Can someone help me with this? I'm stuck on the calculations :( I appreciate the help!!

Partner's Name: instructor?s Initials: Molarity of Stock KMnO4 solution: 0.021M Molarity of diluted KMnO4 solution: Part 1 Trial 1 Trial 2 Trial 3 Initial volume of KMnO4 10.0mL 8.10mL 6.30mL Final Volume of KMnO4 8.10mL 6.30mL 4.40mL Volume of KMnO14 used for Titration 1.90mL 1.80mL 1.90mL mmoles of MnO4- mmoles of C2O42- [C2O42-] [Ba2+] Ksp Show your calculations for Trial I below. Show your calculations for the Ksp of barium oxalate from the solubility you found in The CRC Handbook of Chemistry and Physics.

Explanation / Answer

I am doing it dor trial 1, you can do it for other 2.

Molarity = n / V

0.021 = n / 1.9

:. N = 0.0399 mmoles

Moles of C2O4 2- will be same as moles of KMnO4

:. Moles of C2O4 2- = 0.0399 mmoles

For [C2O4] 2- volume of C2O4 would be required. And same for all the other things.

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