What is ? H ?rxn for the following chemical reaction? H2O(l)+CCl4(l)?COCl2(g)+2H

Question

What is ?H?rxn for the following chemical reaction?

H2O(l)+CCl4(l)?COCl2(g)+2HCl(g)

You can use the following table of standard heats of formation (?H?f) to calculate the enthalpy of the given reaction.

Express the standard enthalpy of reaction to three significant figures and include the appropriate units.

Element/ Compound Standard Heat of Formation (kJ/mol) Element/ Compound Standard Heat of Formation (kJ/mol) H(g) 218 N(g) 473 H2(g) 0 O2(g) 0 CCl4(l) ?139.5 O(g) 249 H2O(l) ?285.8 HCl(g) ?92.30kJ C(g) 71 COCl2(g) ?218.8kJ C(s) 0 HNO3(aq) ?206.6

Explanation / Answer

DH= DH(COCl2)+2* DH(HCl)-DH(H2O) -DH(CCl4)

DH=-218.8+2*(-92.30)+285.8+139.5

DH= 21.9kj/mole

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