Consider the quantum numbers n = 4 and 1-2. Which of the following statements ar
ID: 847024 • Letter: C
Question
Consider the quantum numbers n = 4 and 1-2. Which of the following statements are correct regarding these quantum numbers? More than one may be correct. corresponds to a p-orbital can hold up to 4 electrons ml can only equal-1, 0,+1 has 5 orbitals ms can only equal ± 1 /2 an electron with these quantum numbers could have an electron configuration of [Kr] 5s2 4d electron configuration of [Kr] 5s 4d an electron at these quantum numbers has more energy than an electron at n = 5, 0 when the last electron in the ground state has these quantum numbers, the atom is between Scandium and Zinc on the Periodic Table orrect.Explanation / Answer
Given n =4, l =2
n refers to shell number and l refers to subshell.
Shell 4 contains 4 subshells. They are l=0, l=1, l=2 and l=3 which are denoted as 4s, 4p, 4d and 4f subshells respectively.
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The given quantum numbers does not belong to p-orbital because l=2 refers to d-orbital.
Therefore, first option is wrong.
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d-orbital hold can hold maximum of 10 electrons.
Therefore, the statement 'can hold up to 4 electrons' is correct.
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ml of 4d shell are -2, -1, 0, +1, +2. Therefore, third option is wrong.
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The number fo orbitals is equal to ms of that quantum number. The ms of 4d subshell contains 5 values.
Therefore, the statement 'has 5 orbitals' is correct.
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ms refers to electron spin and the ms values for any orbital has two values. Ther are +1/2 and -1/2.
Therefore, the statement 'ms can only equal +1/2 and -1/2' is correct.
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The electron configuration [Kr] 5s2 4d3 contains 4d shell.
Therefore, the statement 'eletron with these quantum numbers could have an configuration of [Kr] 5s2 4d3' is correct.
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As the shell number increases, the energy of the shell also increases. Thus, n =4 shell orbital will have less energy n = 5 shell.
Therefore the statement 'an electron at these quantum numbers has more energy than an electron at n=5, l=0'is wrong.
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Electron congurations for scandium and zinc are [Ar] 3d1 4s2 and [Ar] 3d10 4s2 respectively. Both the elements has the electron in
its least orbital of sheel-4.
The electron in n =4 at its least shell l=0 is exists at 4s orbital.
Therefore, the statement 'last electron in the ground state has these quantum numbers, the atom is between sacandium and
zinc on periodic table'is correct.