All of the following reactions are exothermic. For which of these reactions (if
ID: 849670 • Letter: A
Question
All of the following reactions are exothermic. For which of these reactions (if any) will you produce a higher temperature by running the reaction in an open container than you will by running the reaction in a sealed, rigid container? Explain briefly. The reaction below is endothermic. Will you produce a lower temperature by running the reaction in an open container or in a sealed, rigid container? When 6.317 g of solid A1 reacts with excess Cl2 gas at constant pressure and 25 degree, 164.9 kJ of heat is produced. Calculate AH and AE for the following reaction at 25 degree: How much heat will be produced if 8.493 g of solid A1 reacts with 29.610 g of gaseous Cl2 in a sealed, rigid container at 25 degree? A chemist bums 0.5177 g of liquid hexane (C6H14) in a bomb calorimeter that has a heat capacity of 4287 J/ degree. The temperature of the calorimeter rises from 21.382 degree to 27.180 degree during the reaction. Calculate AH and AE for the following reaction at 25 degree: Using the enthalpies of formation in Appendix 4 of your textbook, calculate the amount of heat that will be released when 5.00 g of solid NaNO3 reacts with excess graphite in an open container. The chemical equation for this reaction is: Acetonitrile (C2H3N) is a liquid that reacts with oxygen as follows: Using this information and the enthalpies of formation in Appendix 4 of your textbook, calculate the enthalpy of formation (delta H ) of C2H3N(l). The heat of vaporization ( delta Hvap) of C2H3N is 825 J/g. Use this value and your answer from question (a) to calculate the enthalpy of formation of C2H3N(g).Explanation / Answer
Solution for Ques 11.
You know the enthalpies of formation from the text book , so 4 mole of NaNO3 would produce 2 moles of Na2O and 2 moles of N2 and 5 moles of CO2...therefore 5gm of NaNO3 i.e. (5 / 85) moles = 1/17 moles of NaNO3 would produce 1/34 moles of Na2O and 1/34 moles of N2 and 5/68 moles of CO2 . So using the mole enthalpies which is energy used to make a mole of the substance, you can get the result by
Heat released = (1/17)*Enthalpy(NaNO3) - (1/34)*Enthalpy(Na2O) - (1/34)*Enthalpy(N2) - (5/68)*Enthalpy(CO2)