Consider an electrochemical cell constructed from the following half-cells that

Question

Consider an electrochemical cell constructed from the following half-cells that are linked together by a porous membrane. (1) an Au electrode dipped into 1.0 M Au(NO3)3 and (2) an Fe electrode dipped into 1.0 M FeSO4. Answer the following questions:

1. Which electrode is the cathode?

2. What emf should the cell generate?

3. In what direction will electrons flow in the outer circuit?

4. Toward which electrode will positive ions migrate?

from Fe to Au

1.94 V

gold

gold

  

1. Which electrode is the cathode?

2. What emf should the cell generate?

3. In what direction will electrons flow in the outer circuit?

  

4. Toward which electrode will positive ions migrate?

A.

from Fe to Au

B.

1.94 V

C.

gold

D.

gold

Explanation / Answer

standerd reduction potential of Au3+ / Au is more than that of Fe2+ / Fe. Thus Au3+ / Au will oxidse Fe2+ / Fe.

1. (c) gold is the cathode

2.(b) E0cell = E0cathode - E0anode = 1.50 -(-0.44) = 1.94 V

3.(a) electron flow will be from anode to cathode

4(d)+ve ions that is cation will go to cathode which is gold

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