Question
Please solve this equilibrium constant question step by step
Hydrogen and carbon dioxide react at a high temperature to give water and carbon monoxide. H2(g) + CO2(g) H2O(g) + CO(g) Laboratory measurements at 986 *C show that there are 0.11 mol each of CO and H2O vapor and 0.087 mol each of H2 and CO2 at equilibrium in a 50.0-L container. Calculate the equilibrium constant for the reaction at 986 degree C. Suppose 0.010 mol each of H2 and CO2 are placed in a 200.0-L container. When equilibrium is achieved at 986 degree C, what amounts of CO(g) and H2O(g), in moles, would be present? [Use the value of K from part (a).]
Explanation / Answer
H2 + CO2 = H2O + CO
0.087 mol