Carbon monoxide + nitrogen dioxide --> carbon dioxide + dinitrogen trioxide At e

Question

Carbon monoxide + nitrogen dioxide --> carbon dioxide + dinitrogen trioxide
At equilibrium with a temp of 27.0 C, a 1.00 L flask is found to have 0.224 atm carbon monoxide, 0.386 atm nitrogen dioxide, 1.43 atm carbon dioxide and 3.35 arm dinitrogen trioxide. 1. Balance the above redox reaction 2. Determine Kp and Kc 3. Calculate delta G 4. Ecell Carbon monoxide + nitrogen dioxide --> carbon dioxide + dinitrogen trioxide
At equilibrium with a temp of 27.0 C, a 1.00 L flask is found to have 0.224 atm carbon monoxide, 0.386 atm nitrogen dioxide, 1.43 atm carbon dioxide and 3.35 arm dinitrogen trioxide. 1. Balance the above redox reaction 2. Determine Kp and Kc 3. Calculate delta G 4. Ecell
At equilibrium with a temp of 27.0 C, a 1.00 L flask is found to have 0.224 atm carbon monoxide, 0.386 atm nitrogen dioxide, 1.43 atm carbon dioxide and 3.35 arm dinitrogen trioxide. 1. Balance the above redox reaction 2. Determine Kp and Kc 3. Calculate delta G 4. Ecell

Explanation / Answer

Carbon monoxide + nitrogen dioxide --> carbon dioxide + dinitrogen trioxide

CO + NO2 -----> CO2 +N2O3

1. balanced reaction is CO + 2NO2 -----> CO2 +N2O3

2. Kc= p[CO2] p[N2O3]/ p[CO]p[NO2]2

Kc= 1.43*3.35/ 0.224*(0.386)2 = 143.42 atm-1

Kp=Kc(RT)?n

?n= 2-3= -1

Kp=143.32(0.0821*300) -1

Kp= 5.822 atm -2

3. ?G= -2.303RTlogKp

?G = -2.303*.0821*300 log(5.822)

?G= -43.39Kj/mol

4. ?G= -nFEcell

Ecell= ?G/nF= -43390 J/mol/ 1*96500= 0.45 V

Ecell= 0.45V

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