Mass weighing bottle + aluminum Mass of weighing bottle Mass of aluminum Concent

Question

Mass weighing bottle + aluminum Mass of weighing bottle Mass of aluminum Concentration and volume of KOH Concentration and volume of H2SO4 Mass weighing bottle and Alum Mass of weighing bottle Mass of Alum 12.11 g 11.04 g 1.07 g 3 M and 20 mL 9 M and 20 mL 25.18 g 11.04g 14.14 g Mass of Aluminum used = 1.07 g Molar Mass of Aluminum = 26.98 g / moles Number of moles Al Mass of Al (g) Molar mass of Al (g/ moles) Number of moles Al = 1.07 g/ 26.98 (g / moles) = 0.0397 moles Since, 2 moles of Aluminum gives 2 moles of Alum. So, there is ration of 1:1 Numbers of moles of Alum = 0.0397 moles Molar mass of Alum = 474.39 g / mole Mass of Alum yielded Number of moles * Molar mass of Alum

Explanation / Answer

If the aluminium is all converted into alum then the relation is 1:1, so you have that

Molar mass of Alum = 14.14 g/0.0397 mol = 356.17 g/ mol.

So 474.39 it's wrong , at least with the information given

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