The metabolism of glucose, C6H12O6, yields carbon dioxide, CO2(g), and water, H2
ID: 875964 • Letter: T
Question
The metabolism of glucose, C6H12O6, yields carbon dioxide, CO2(g), and water, H2O(l), as products. Energy released in this metabolic process is converted to useful work, w, with about 72.0 % efficiency. Use the data below to answer questions about the metabolism of glucose.
Calculate the mass of glucose metabolized by a 79.8 kg person in climbing a mountain with an elevation gain of 1910 m . Assume that the work performed in the climb is four times that required to simply lift 79.8 kg by 1910 m .
Substance ?H?f(kJ/mol) CO2(g) ?393.5 C6H12O6(s) ?1273.3 H2O(l) ?285.8 O2(g)
Explanation / Answer
Solution :-
Given data
Mass of person= 79.8 kg
Elevation = 1910 m
Efficiency = 72.0 %
Mass of glucose = ?
Lets first calculate the energy give by 1 mole of glucosefrom the given standard enthalpy of formation of values of the reactant and product.
Lets first write the balanced reaction equation
C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(l)
Now lets calculate the enthalpy of reaction using the Hess