Some reactants do not go to completion but rather reach a point of equilibrium b

Question

Some reactants do not go to completion but rather reach a point of equilibrium between the products and the reactants. Given the reaction below, suppose you start with 4.56 moles of A. The reaction reaches equilibrium and at equilibrium the are only 1.39 moles of A left. How many moles of B and how many moles of C have you made?
2A --> 3B +C Some reactants do not go to completion but rather reach a point of equilibrium between the products and the reactants. Given the reaction below, suppose you start with 4.56 moles of A. The reaction reaches equilibrium and at equilibrium the are only 1.39 moles of A left. How many moles of B and how many moles of C have you made?
2A --> 3B +C Some reactants do not go to completion but rather reach a point of equilibrium between the products and the reactants. Given the reaction below, suppose you start with 4.56 moles of A. The reaction reaches equilibrium and at equilibrium the are only 1.39 moles of A left. How many moles of B and how many moles of C have you made?
2A --> 3B +C

Explanation / Answer

            2A            -->    3B + C

Initial            4.56               0       0

Change        -2x                   3x      x

Equilibrium   4.56-2x              3x      x

Given equilibrium conentration of A = 1.39 moles

so 4.56- 2x = 1.39 moles

or 2x = 3.17 moles

x = 1.59 moles

so equilibrium conentration of B and C are

[B] = 3x = 3X1.59 = 4.77 moles

[C] = x = 1.59 moles

So we have made 4.77 moles of B and 1.59 moles of C

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