Consider the decomposition of acetaldehyde (CH 3 CHO) into methane (CH 4 ) and c

Question

Consider the decomposition of acetaldehyde (CH3CHO) into methane (CH4) and carbon monoxide (CO).

Consider the decomposition of acetaldehyde (CH3CHO) into methane (CH4) and carbon monoxide (CO) CH3CHO CH4 + CO An experiment is performed where the concentration of acetaldehyde is measured at various time intervals, resulting in the following data Time (s) [CH3CHo] (M) 0.0 20.0 40.0 60.0 0.257 0.179 0.137 (a) Graphically draw the three plots below and determine the order of the reaction with respect to CH3CHO. (Enter your answer to three significant figures.) graph (1): [CH3CHO]t vs. time [CH3 CHO]l (M) 0.30 0.25 0.20 0.15 0.10 0.05 Time (s) 20.0 40.0 60.0 80.0 slope = y-intercept

Explanation / Answer

Rate = -d[reactants] / dt

from given data, [CH3CHO] = [CH3CHO]FINAL - [CH3CHO]INITIAL

                                                                 = 0.179 - 0.257 = -0.078M

t = 20- 0 = 20s

Rate = -(-0.078)/20 = 0.0039 mol lit-1sec-1

From the above data

a)From the rate equation Rate = [CH3CHO]n ,n = order of rection

0.0021/0.0013 = 0.137n / 0.111n

1.61538 = 1.234n

n = 2.279

b)Rate constant = rate / [CH3CHO]2.279

                       = 0.0013 / 0.1112.279

                        = 0.194844 lit1.279mol-1.279sec-1

c)Rate equation is

Rate = k [CH3CHO]2.279

time conc rate 20 0.179 0.0039 40 0.137 0.0021 60 0.111 0.0013

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