Biochemistry, Please help with 1 and 2!!! L. You need to prepare a buffer for bi
ID: 885499 • Letter: B
Question
Biochemistry, Please help with 1 and 2!!!
Explanation / Answer
1) We can prepare buffer solution by using a weak acid and its salt of strong base:
so here weak acid is: NaH2PO4 and its salt is Na2HPO4
Hendersen Hasselbalch equaiton for buffer is
pH - pKa + log [salt] / [acid]
pKa = 7.2
7 = 7.2 + log [salt] / 0.5
-0.2 = log [salt] / 0.5
taking antilog
0.631 = [salt] / 0.5
[salt] = 0.315
so concentration = 0.315 M
Volume of solution = 1L
So moles of dibasic sodium phosphate = moalrity X volume= 0.315 X 1 = 0.315 moles
gram of dibasic sodium phosphate = moles X molecular weight = 0.315 X 142 = 44.73 grams
2) we can preapre the buffer by adding NaOH to sodium phophate
pH = 7 = 7.2 + log [salt] / [acid]
so the volume of solution = 1L
NaOH + NaH2PO4 --> Na2HPO4
So the amount of added sodium hydroxide will react with monosodium phosphate to give equal mole of disodium phophate.
concentration ratio of salt / acid = 0.315
[salt] = 0.315 [acid]
so take moles of sodium hdyroxide 0.315 times of acid that will be left in acid
so take 0.63 moles of acid and add 0.315 moles of naOH to it.