In Europe, gasoline efficiency is measured in km/L. If your car\'s gas mileage i
ID: 889374 • Letter: I
Question
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 22.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.
While in Europe, if you drive 107 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 28.0 mi/gal ? Assume that 1euro=1.26dollars.
A sprinter set a high school record in track and field, running 200.0 m in 20.8 s . What is the average speed of the sprinter in kilometers per hour?
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece. How many kilograms of dietary fat are in a box containing 4.00 lb of candy?
Explanation / Answer
1km=0.6214mi
or
0.6214mi = 1km
Therefore
22.0 mi = 1km x 22.0 mi / 0.6214 mi = 35.4 km
1gal=3.78L.
The car's gas mileage is 22.0 mi/gal = 35.4 km/3.78L.
The number of liters of gasoline needed to cover 35.4 km = 3.78L
The number of liters of gasoline needed to cover 142 km = 3.78L x 142 km / 35.4 km = 15.16 L
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0.6214mi = 1km
Therefore
28.0 mi = 1km x 28.0 mi / 0.6214 mi = 45.06 km
1gal=3.78L.
The car's gas mileage is 28.0 mi/gal = 45.06 km/3.78L.
The number of liters of gasoline needed to cover 45.06 km = 3.78L
The number of liters of gasoline needed to cover 107 km = 3.78L x 107 km / 45.06 km = 8.97 L
The number of liters of gasoline needed for 1 day = 8.97 L
The number of liters of gasoline needed for 7 days (1week) = 7x 8.97 L = 62.79 L
Cost of 1 L of gasoline = 1.10 euros
Therefore
Cost of 62.79 L of gasoline = 62.79 x1.10 euros = 69.07 euros
1 Euro = 1.26 dollars.
Therefore , 69.09 euros = 69.07 x 1.26 dollars.= 87.03 dollars
The money that would you spend on gas in one week = 87.03 dollars
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200.0 m = 0.200 km
20.8 s = [20.8 / (60x60) ] hour
200.0 m in 20.8 s = 0.200 km in [20.8 / (60x60)] hour
Average speed in = Distance in km/ Time in hour = [(0.200 x60x60 ) / 20.8] km/hour = 34.6 km/hour
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1 lb = 453.6 g
or
453.6 g = 1lb
Therefore
22.7 g = 1lb x 22.7 g / 453.6 g = 0.05 lb
7.00 g of dietary fat is present in each 22.7-g piece. or 0.05 lb piece
0.05 lb piece contains 7.00 g of dietary fat
Therefore
4.00 lb of candy will contain 7.00 g x 4.00 lb / 0.05 lb = 560 g of dietary fat = 0.560 kg of dietary fat
The number of kilograms of dietary fat are in a box containing 4.00 lb of candy = 0.560 kg
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