For the genetic trait of interdigital hair (hair between your knuckles), this ph
ID: 8920 • Letter: F
Question
For the genetic trait of interdigital hair (hair between your knuckles), this phenotype is controlled by one gene. In a population, you determine that the frequency of the alleles is 0.55 H and 0.45 h, with HH being dominant and hairy. If the observed genotype ratio is 0.25 HH, 0.55 Hh and 0.2 hh, is this population at Hardy Weinberg equilibrium? (Show your work to do this calculation). If not, what are the Hardy-Weinberg genotype ratios?If the population is not at equilibrium, what are three different reasons that it might not be?
Explanation / Answer
the population is in HARDY WEINBERG EQUILIBRIUM
H h
Parental 0.55 0.45
F1 0.55 0.45
F2 0.55 0.45
F3 0.55 0.45
that the frequency of the alleles is 0.55 H and 0.45 h
frequency of the alleles is 0.55 H ----------------p
and 0.45 h---------------------------------q
according to H.W.E p2+2pq+q2
p2-------------------0.55 x0.55---------------0.3025
2pq-----------2x0.55x0.45------------------0.495
q2------------------0.45 x0.45----------------0.2025
1
F1 generation
By using gene count method
frequency of the alleles H= p2+ 2pq/2=0.3025+0.495/2=0.55
frequency of the alleles h= q2+ 2pq/2=0.2025+0.495/2=0.45
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