Please, I want you to help out with my answers from my last exam. Some of them a
ID: 90285 • Letter: P
Question
Please, I want you to help out with my answers from my last exam. Some of them are right and some and some wrong. Can you please help me out by checking the answers and fixing my mistakes. I only need from Q13 till 32.
Thank YOU!!
11-12. Refer to the figure to the right. Arg: R 11. The three amino acids shown (2 points) are hydrophilic. b are hydrophobic. Ehave positively charged R groups. d. form disulfide bridges. e, are smaller than the other amino 12. During the creation of a peptide backbone, these amino acids will form disulfide bridges. ester linkages. e. hydrogen bonds. ptide bonds. e. glycosidic linkages. Method 13-14. Refer to the diagram to the right depicting Oswald Avery's experiment investigating transformation. S strain 13. The experiment depicted was a. how mice respond to infection with Streptococcus pneumonia b. which macromolecules are most stable c) which macromolecule contained the genetic information d, what type of molecule viruses inject into E coli bacteria R strain 14. Circle the that were obtained result for each of the conditions in this experiment (3 points) Mice injected with these bacteria: circle one answer for each condition) die Glutamic acid (Glu; vell die liveExplanation / Answer
13. Oswald Avery’s experiment investigating transformation showed that DNA carries the genetic or hereditary information that was responsible for transformation of rough strain (without capsule) to virulent smooth strain (with capsule and exposed antigens) of bacterium. So, the correct option is option C, which macromolecule contained the genetic information.
14. Mice injected with RNase treated bacterium will die as RNase enzyme catalyzes the denaturation of RNA but not DNA.
Mice injected with protease treated bacterium will die as protease enzyme catalyzes the denaturation of proteins but not DNA.
Mice injected with DNase treated bacterium will live as DNase enzyme catalyzes the denaturation of DNA and hence DNA is not transferred from S strain of bacterium to the R strain of bacterium.
15. Cellulose/triglyceride is not a correct monomer/polymer pairing as cellulose is a structural polysaccharide while triglycerides are esters derived from glycerol and three fatty acids. So, the correct option is option C, cellulose/triglyceride.
16. Carbohydrates are polyhydroxy aldehydes or ketones consisting of carbon, hydrogen, and oxygen atoms. So, the correct option is option D, C, H, and O.
17. Cellulose is a structural polysaccharide found in the cell wall of plants and it provides mechanical strength to the cell wall. So, the correct option is option E, to provide mechanical strength to plant cell walls.
18. Vegetable oils are liquids at room temperature. The process of addition of hydrogen to these oils to reduce the number of carbon-carbon double bonds is known as hydrogenation and such oils are known as hydrogenated vegetable oils. These oils are used in the manufacturing of food items like biscuits, cakes etc. These oils are solids at room temperature. So, the correct option is option B, oil is now solid at room temperature.
19. Amino acids have an amino group, a carboxyl group and an organic R group also known as the amino acid side chain. The amino acids differ from each other based on the chemical structure of their R group. So, the correct option is option D, “R”.
20. The three dimensional structure of a protein is determined by the primary structure or the amino acid sequence of the protein. This is known as the thermodynamic hypothesis or the Anfinsen’s dogma. So, the correct option is option B, the sequence of its amino acids.
21. Peptides are small chains of amino acids linked by peptide or amide bonds. A peptide chain (except for cyclic peptide) has an N-terminal and a C-terminal residue at the end of the peptide chain. So, the correct option is option C, N terminus; C terminus.
22. Two types of secondary structures are found in proteins- alpha helices and beta pleated sheets. So, the correct option is option B, secondary structure.
23. Protein denaturation disrupts the secondary and tertiary structures of the protein. The denaturation reactions are not too strong to break the peptide bonds and hence the primary structure remains unchanged after denaturation. So, the correct option is option D, both b and c.
24. The primary structure of DNA has 2 parts – 1. The backbone of DNA made up of deoxyribose sugar and phosphate groups and 2. the nitrogenous bases that are the side chains of the DNA molecule. So, the correct option is option C, nitrogenous bases.
25. The four nitrogenous bases of RNA are adenine, uracil, guanine, and cytosine. So, the correct option is option C: A, G, C, and U.
26. DNA is double stranded molecule while RNA is single stranded molecule. DNA has thymine and RNA has uracil as a nitrogenous base. DNA does not leave the nucleus while RNA leaves the nucleus after RNA procession for translation to a protein. DNA is made of deoxyribose sugar while RNA is made of ribose sugar. So, the correct option is option E, all of the above.
27. Interactions between 2 or more secondary structures form the tertiary structure of RNA. Tertiary interactions consist of base stacking and hydrogen bond interactions. The folds of three dimensional structures of RNA such as the tRNA are stabilized by hydrogen bonds. So, the correct option is option A, hydrogen.
28. DNA molecule is made up of nitrogenous bases and each gene has a specific sequence of bases that code for different products. So, the correct option is option B, sequence of bases.
29. Prior to Hershey-Chase experiment many biologists assumed that proteins carried the genetic information as DNA appeared to be simpler than proteins. So, the correct option is option C, are more structurally diverse than DNA.
30. Adenine pairs with thymine and guanine pairs with cytosine. According to Chargaff’s rule %A = %T and %G = %C for a double stranded DNA molecule. If the DNA molecule has 30% T, then A = 30% and A+T = 60%. The remaining 40% is made up of G+C. Since %G = %C, G = 20% and C = 20%. So, the correct option is option A, 20%.
31. DNA is a right handed double stranded helical molecule with a uniform diameter of 2 nm (20 angstrom units). The two strands of DNA run in opposite directions. So, the correct option is option E, all of the above are true, none is false.
32. In DNA, A pairs with T and G pairs with C. The complementary strand for the sequence given is 3’- TCGACGACT -5’. So, the correct option is option D, 3’- TCGACGACT -5’.