Can you help me with problems 3 and 7 please. chanisfoon Write a mechanism for t
ID: 903302 • Letter: C
Question
Can you help me with problems 3 and 7 please. chanisfoon Write a mechanism for the reduction Ul 0l under the reaction conditions you used. Exerci503 on the s commer paperma of sodium borohy 4. Starthig iu 2 Write a balanced equation for the decomposition of sod Describe and explain the possible effect on your results of alcohol. (a) You used pure water as the reaction solvent, C ent. (b of the follow flo ing experimental errors or variations during the synthesis oe fol 5 mL of 1 M NaOH for the NaBH4 solution and 10 mL o O dride in water to which HCl has been added e yYouused with 25 mo and uwed th 10 mL of 1 MNade 25 mmol of v for the vanillin solution.(c) Because you started with 25 mmo mol andusa you assumed that a 100% excess of NaBH4 was 50 m amount. 4. (a) Calculate the atom economy and reaction efficiency of your svout (b) Describe some green features of your synthesis, and any that arent green. struct a flow diagram for the experiment. Explain why it is better to add the NaBH4 solution to a base 5. Following the format in the "Planning an Experiment" a eriment" appendix, con a reducing agent. a base-sensitive 6. Sodium borohydride is a strong base as well as a reducing substrate than to add the substrate to the NaBH4 solution. (a) Draw the structure of the product you would have isolated if wou had used NaBD, in D2O in this experiment, and write a mechanism explaining the result. (b) Give the product structure for the same reac. tion using NaBD, in H2O. Assume that there is no hydrogen exchange between NaBD, and the solvent. 8. A careless student, Will Bobble, misread the label on a bottle of 10 M sodium hydroxide and used it (rather than 1 M NaOH) to dissolve hisExplanation / Answer
There are multiple questions here . i am allowed to answer only 1 at a time. I will answer 2nd question for you since question 1 is not visible properly. Please ask other as different question.
2.
Here Boric acid will be formed.
NaBH4(s) + HCl(aq) + 3 H2O(l) = NaCl(aq) + H3BO3(aq) + 4 H2(g)
you can see bubbling due to release of Hydrogen gas