Please i need help woth this. thanks. When solutions of silver nitrate and magne

ID: 904557 • Letter: P

Question

Please i need help woth this. thanks.

When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation

2AgNO3(aq)+MgCl2(aq)2AgCl(s)+Mg(NO3)2(aq)

Part A

What mass of silver chloride can be produced from 1.27 L of a 0.120 M solution of silver nitrate?

Express your answer with the appropriate units.

Part B

The reaction described in Part A required 3.60 L of magnesium chloride. What is the concentration of this magnesium chloride solution?

Express your answer with the appropriate units.

Part A

The moles of silver nitrate - (Molarity of Silver nitrate x Volume of solution)/1000

The Conversion of L to mL = 1.27 x 1000 = 1270 mL

The moles of silver nitrate - (1270*0.120)/1000 = 0.1524 M

2 moles of silver nitrate is reacted to produce 2 moles of silver chloride

Then moles of silver chloride = 2 x 0.1524 = 0.3048 M

Hence mass of silver chloride that is produced = (moles of silver chloride x Molecular weight of silver chloride) = 43.38 grams

Part B

The moles of magnesium chloride solution = moles of MgCl2 x Volume of the solution

= 0.1524 x 3.6 or (0.1524 *3600)/1000

= 0.5486 M

Mass of magnesium chloride = 0.5486 x 95.211 = 52.24 grams