Part A) If the two genes are 10 mu apart and the plant is (AB/ab) , what proport
ID: 91232 • Letter: P
Question
Part A) If the two genes are 10 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be AB?
Part B) If the two genes are 10 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be Ab?
Part C) If the two genes are 10 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be aB?
Part D) If the two genes are 10 mu apart and the plant is (AB/ab), what proportion of gametes from a signal plant will be ab?
Part E) What proportion of the offspring of two plants ( both (AB/ab)) will be A_B_ if the genes are 10 mu apart?
Part F) What proportion of the offspring of two plants ( both (AB/ab)) will be A_bb if the genes are 10 mu apart?
Part G) What proportion of the offspring of two plants ( both (AB/ab)) will be aaB_ if the genes are 10 mu apart?
Part H) What proportion of the offspring of two plants ( both (AB/ab)) will be aabb if the genes are 10 mu apart?
Enter your answers as a decimal to three places (for example: 0.120).
Problem 5.27 Two plants in a cross were each heterozygous for two gene pairs (AB/ab) whose loci are linked and 10 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.) Assuming that crossing over occurs during the formation of both male and female gametes and that the A and Balleles are dominant, determine the phenotypic ratio of their offspring.Explanation / Answer
Answer:
Answer:
A).The proportion of gametes from a single plant will be AB = 45% or 0.45
B).The proportion of gametes from a single plant will be Ab = 5% or 0.5
C).The proportion of gametes from a single plant will be aB = 5% or 0.5
D).The proportion of gametes from a single plant will be ab = 45% or 0.45
E). The proportion of the offspring of two plants (both (AB/ab)) will be A_B_ if the genes are 10 mu apart = (2* 0.2025) + (2*0.0025) = 0.41
F). The proportion of the offspring of two plants (both (AB/ab)) will be A_bb if the genes are 10 mu apart = (2*0.0225) + 0.0025 = 0.048
G). The proportion of the offspring of two plants ( both (AB/ab)) will be aaB_ if the genes are 10 mu apart = (2*0.0225) + 0.0025 = 0.048
H). The proportion of the offspring of two plants ( both (AB/ab)) will be aabb if the genes are 10 mu apart = 0.203
Explanation:
Distance between the genes (mu) = recombination frequency (%)
10 mu = 10% or 0.1
Recombinant gametes, Ab & aB = 10% (Ab= 5% & aB=5%)
Parental gametes, AB & ab = 90% = 0.9(AB= 45% & ab=45%)
AB / ab x AB / ab ------------------Parents
AB (0.45)
Ab (0.05)
aB (0.05)
Ab (0.45)
AB (0.45)
AABB (0.2025)
AABb (0.0225)
AaBB (0.0225)
AaBb (0.2025)
Ab (0.05)
AABb (0.0225)
AAbb (0.0025)
AaBb (0.0025)
Aabb (0.0225)
aB (0.05)
AaBB (0.0225)
AaBb (0.0025)
aaBB (0.0025)
aaBb (0.0225)
ab(0.45)
AaBb (0.2025)
Aabb (0.0225)
aaBb (0.0225)
aabb (0.2025)
AB (0.45)
Ab (0.05)
aB (0.05)
Ab (0.45)
AB (0.45)
AABB (0.2025)
AABb (0.0225)
AaBB (0.0225)
AaBb (0.2025)
Ab (0.05)
AABb (0.0225)
AAbb (0.0025)
AaBb (0.0025)
Aabb (0.0225)
aB (0.05)
AaBB (0.0225)
AaBb (0.0025)
aaBB (0.0025)
aaBb (0.0225)
ab(0.45)
AaBb (0.2025)
Aabb (0.0225)
aaBb (0.0225)
aabb (0.2025)