Please explain and show all steps, thank you. Given that water melts at 0 degree
ID: 915457 • Letter: P
Question
Please explain and show all steps, thank you.
Given that water melts at 0 degreeC and had a heat of fusion of +6.012 kJ/mol, what is the melting point for a saturated aqueous NaCl solution (35.7 g NaCl / 100 g H20)? a. Use the simplified equation Delta T= XA . Tmelt^2.R/Delta fus H b. Use Mathematica to solve: (T melt - T2,)=-In(1 - XA).T melt^2 .R/ Deltafus H .Note that the meaning of AT above is reversed from the boiling point elevation (#3 a) because the temperature change is negative for freezing point depression. Also, the experimental value of DeltaT is 21degree C.Explanation / Answer
xa = grams of A/total grams
xa = 35.7/135.7 = 0.263
a) deltaT = 0.263*(273.15^2)*(0.008314) / 6.012
deltaT = 27.13 ºC or ºK
b) 273.15 - T2 = (-ln(0.737)*(273.15^2)*0.008314)/(6.012)
T2 = 31.488 ºC