Map sapling learning Substance(kJ/mol) M20(s) |-8.00 M(s) O2(9) Consider the dec

Question

Map sapling learning Substance(kJ/mol) M20(s) |-8.00 M(s) O2(9) Consider the decomposition of a metal oxide to its elements, where M represents a generic metal 2MIs+ - 0 What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? Number k.J/ mol What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K? Number What is the equilibrium pressure of O2(g) over M(s) at 298 K? Number atm Previous Give Up & View Solution e Check Answer Next Exit Hint

Explanation / Answer

M20 ---> 2M + 0.5 02

we know that

dGo rxn = dGo products - dGo reactants

so

dGo rxn = 2 x dgo M + 0.5 x dGo 02 - dGo M20

using given values

dGo rxn = ( 2 x 0) + ( 0.5 x 0) - ( -8)

dGo rxn = 8 kJ/mol

2)

now

we know that

dGo - -RT lnKeq

so

8 x 1000 = -8.314 x 298 x ln Keq

Keq = 0.0396

now

the equilibrium constant is 0.0396

3)

now

M20 (s) ---> 2M (s) + 0.5 02 (g)

now

the equilibrium constant is given by

Keq = [p02]^0.5

note : solids are not included in equilibrium constant expression

so

0.0396 = [p02]^0.5

p02 = 1.57 x 10-3

so

the partial pressure of 02 is 1.57 x 10-3 atm

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