What volumes (in liters) of carbon monoxide and oxygen gas must react according

Question

What volumes (in liters) of carbon monoxide and oxygen gas must react according to the equation
2Co(g)+O2(g)---> 2CO2(g) To form 4.01L of Carbon dioxide?
-What is the volume of CO?(L) -What is the volume of O2?(L) What volumes (in liters) of carbon monoxide and oxygen gas must react according to the equation
2Co(g)+O2(g)---> 2CO2(g) To form 4.01L of Carbon dioxide?
-What is the volume of CO?(L) -What is the volume of O2?(L)
2Co(g)+O2(g)---> 2CO2(g) To form 4.01L of Carbon dioxide?
-What is the volume of CO?(L) -What is the volume of O2?(L)

Explanation / Answer

As per the equation

2CO(g)+O2(g)---> 2CO2(g)

two moles of CO will react with one mole of O2 to give 2moles of CO2

Volume is proportional to moles of gases

so as per stoichiometry

for 22.4 L of CO2 we need 22.4 L of CO and 22.4 /2 L of O2

So for 4.01 L of CO2 we will need

CO = 4.01 L

O2 = 2.005 L

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