For the gas phase decomposition of 1-bromopropane , the rate constant has been d

Question

For the gas phase decomposition of 1-bromopropane,

the rate constant has been determined at several temperatures. When ln k in s-1 is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -2.41E4 K and a y-intercept of 31.3.

The activation energy for the gas phase decomposition of 1-bromopropane is ______________ kJ/mol.

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2Br ---> CH3CH=CH2 + HBr the rate constant has been determined at several temperatures. When ln k in s-1 is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -2.41E4 K and a y-intercept of 31.3. The activation energy for the gas phase decomposition of 1-bromopropane is ______________ kJ/mol.

Explanation / Answer

According to Arrhenius equation, we have :

k = Ae(-Ea/RT)

Here, Ea = activation energy

Taking natural ln on both sides, we get :
ln k = -Ea/RT + ln A

For the plot between ln k vs 1/T, we have :
slope = -Ea/R

Given : slope = -2.41*104

Thus, -Ea/R = -2.41*104

Solving we get :

Ea = R*2.41*104 = 8.314*2.41*104 = 200.36 kJ/mol

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