Problem 6.16 In the following reactions, identify what is oxidized, and what is

Question

Problem 6.16

In the following reactions, identify what is oxidized, and what is reduced.

Part A

2Li(s)+F2(g)?2LiF(s)

Cl2(g)+2KI(aq)?2KCl(aq)+I2(s)

Mg(s)+Cu2+(aq)?Mg2+(aq)+Cu(s)

Fe(s)+CuSO4(aq)?FeSO4(aq)+Cu(s)

Problem 6.16

In the following reactions, identify what is oxidized, and what is reduced.

Part A

2Li(s)+F2(g)?2LiF(s)

both Li and F are oxidized both Li and F are reduced Li is oxidized, F is reduced F is oxidized, Li is reduced

Cl2(g)+2KI(aq)?2KCl(aq)+I2(s)

Cl is oxidized, K is reduced K is oxidized, Cl is reduced I is oxidized, Cl is reduced Cl is oxidized, I is reduced

Mg(s)+Cu2+(aq)?Mg2+(aq)+Cu(s)

both Cu2+ and Mg are reduced both Cu2+ and Mg oxidized Cu2+ is oxidized, Mg is reduced Mg is oxidized, Cu2+ is reduced

Fe(s)+CuSO4(aq)?FeSO4(aq)+Cu(s)

Fe is oxidized, Cu2+ is reduced S is oxidized, Fe is reduced Cu is oxidized, Fe is reduced SO4 is oxidized, Cu2+ is reduced

Explanation / Answer

oxidation means when the Oxidation state increases.

reduction means when the Oxidation state is decreases.

1) 2Li(s)+F2(g)?2LiF(s)

lithium goes from 0 oxidation state(OS) to +1 OS

and F from 0 to -1

=> Li is oxidized, F is reduced (option C )

2) Cl2(g)+2KI(aq)?2KCl(aq)+I2(s)

Cl2 from 0 to -1

K from +1 to +1

I from -1 to 0

so, I is oxidized, Cl is reduced (option C)

3) Mg(s)+Cu2+(aq)?Mg2+(aq)+Cu(s)

Mg from 0 to +2

Cu from +2 to 0

=> Mg is oxidized, Cu2+ is reduced (option D )

4) Fe(s)+CuSO4(aq)?FeSO4(aq)+Cu(s)

Fe from 0 to +2

Cu from +2 to 0

SO4 from -2 to -2

=> Fe is oxidized, Cu2+ is reduced (option A)

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