Clarendon College-CHE e The Decomposition Of N2 × -> Dwww.saplinglearning.com/ib
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Clarendon College-CHE e The Decomposition Of N2 × -> Dwww.saplinglearning.com/ibiscms/mod/ibis/view.php?id=2526583 2/19/2016 10:00 PM A 45/100 Assignment Information Available From 2/15/2016 12:00 PMM Due Date: Points Possible: Grade Category: Graded Description: Policies: # Attempts Score Gradebook Print Calculator Periadic Table Question 2 of 22 2/19/2016 10:00 PM Map University Science Books presented by Sapling Learning 100 Donald McQuanrie Peter A. Rock Ethan Gallogy The decomposition of N205 can be described by the equation t(s) N20sl (M) 2.36 2N,05(soln) 4NO2 (soln)+02 Homework 225 2.05 416 1.82 755 1.47 Given these data for the reaction at 45°C in carbon tetrachloride solution calculate the average rate of reaction for each successive time interval You can check your answers. ou can check your answers You can view solutions when you complete or give up on any question. Interval:0s to 225 s 225 s to 416 s Number click to edit Number You can keep trying to answer each question until you get it right or give up. Reaction rate: M/ s M/ s M/ s You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer D Help With This Topic 12 Web Help &Videos; 13 Technical Support and Bug Reports 14 Previous Give Up & View Solution O Check Answer Next Exit 15 Hint Copyright © 2011-2016 Sapling Learning, Inc.-130 about us careers partners privacy policy terms of use contact ushelp 10:46 AM 2/16/2016Explanation / Answer
Rate equation = k=1/t x ln(a/a-x)
initial concentration of N2O5 in solution = (2.36-0) = 2.36 i.e. a =2.36
The values of (a-x) at different intervals of time are
time (t) 225 416 755
(a-x) 0.3 0.54 0.89
k1= 1/225 x ln(2.36/0.3)
9.15x10-3
k2= 1/416 xln(2.36/0.54)
5.02x10-3
k3= 1/755 xln(2.36/0.89)
1.28x10-3
Average rate of reaction = (k1+k2+k3)/3
= (9.15x10-3) + (5.02x10-3) + (1.28x10-3) / 3= 5.15x10-3