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A sample of 58.90 g solid benzene at 2.4°C was heated until it absorbed 13.5 kJ

ID: 939391 • Letter: A

Question

A sample of 58.90 g solid benzene at 2.4°C was heated until it absorbed 13.5 kJ of heat, at a constant pressure of 1 atmosphere. Using the data given in the table below, determine the final phase and final temperature of the benzene sample.

melting point 5.49°C

boiling point 80.09°C

heat of fusion at 5.49°C: 9.87 kJ/mol

heat of vaporization at 80.09°C: 30.72 kJ/mol

molar heat capacity of solid at 0°C: 118.4 J/mol·K

molar heat capacity of liquid at 25°C: 136.0 J/mol·K

molar heat capacity of gas at 95°C: 103.98 J/mol·K

In its final phase, what will the benzene sample final temperature be?

Explanation / Answer

q = m*s*DT

heating benzene solid to 5.49 c

= (58.9/78)*118.4*(5.49+2.4)

= 705.422 joule. = 0.7 kj

conversion of solid to liquid

= n*DHfus

= (58.9/78)*9.87 = 7.45 kj

energy consumed = 7.45+0.7 = 8.15 kj


heating liquid benzene to 80.09 C

5.35*10^3 = (58.9/78)*136*(x-5.49)

final temperature = x = 57.58 C


so that it is in liquid state.