Problem 16.45 Part A Calculate [OH] for 1.2×10 3 M Sr(OH)2. Express your answer
ID: 939498 • Letter: P
Question
Problem 16.45
Part A
Calculate [OH] for 1.2×103 M Sr(OH)2.
Express your answer using two significant figures.
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Part B
Calculate pH for 1.2×103 M Sr(OH)2.
Express your answer using two decimal places.
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Part C
Calculate [OH] for 2.380 g of LiOH in 300.0 mL of solution.
Express your answer using four significant figures.
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Part D
Calculate pH for 2.380 g of LiOH in 300.0 mL of solution.
Express your answer using four decimal places.
[OH] = MExplanation / Answer
Part A:
[OH-] = 2 x 1.2 x 10^-3 = 0.0024 M
Part B:
pOH = -log[OH-] = 2.6
pH = 14 - pOH = 14 - 2.6 = 11.4
Part C:
moles LiOH = 2.380 g/ 23.948 g/mol=0.09938
[OH-]= 0.09938 / 0.3 L=0.3313 M
Part D:
pOH = -log[OH-] = 0.4798
pH = 14 - pOH = 14 - 0.4798 =13.52