A benzene-toluene solution with Xben=0.300 has a nbp ( normal boiling point) of

Question

A benzene-toluene solution with Xben=0.300 has a nbp ( normal boiling point) of 98.6degrees. The vap.pre. of pure toluene at 98.6degrees is 533 mmHg. What must be the vap.pre. of pure benzene at 98.6degrees? (Assume ideal solution behaviour.) Pben (observed)=XbenPben (pure) & Ptol=XtolPtol A benzene-toluene solution with Xben=0.300 has a nbp ( normal boiling point) of 98.6degrees. The vap.pre. of pure toluene at 98.6degrees is 533 mmHg. What must be the vap.pre. of pure benzene at 98.6degrees? (Assume ideal solution behaviour.) Pben (observed)=XbenPben (pure) & Ptol=XtolPtol Pben (observed)=XbenPben (pure) & Ptol=XtolPtol

Explanation / Answer

the boiling point of solution = 98.6 C . at thisconditions the vapour pressure = 760 mmhg.

Vapressure of solution = pben+ pTou

   760 = 533 + x

x = Vapressure of benzene = 227 mmhg.

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