In the reaction of aqueous solutions of strontium nitrate with sodium sulfate th
ID: 945552 • Letter: I
Question
In the reaction of aqueous solutions of strontium nitrate with sodium sulfate the correct balanced complete ionic equation is
Sr(NO3)2(aq) + 2Na+(aq) + SO42-(aq) ----> SrSO4(aq) + 2Na+ (aq) + 2NO31-(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> Sr2+(aq) + SO42-(aq) + 2Na+(aq) + 2NO31-(aq)
Sr2+(aq) + NO31-(aq) + Na+(aq) + SO42-(aq) ----> Sr2+(aq) + SO42-(aq) + Na+(aq) + NO31-(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> SrNa2(s) + SO4NO3(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> SrSO4(s) + 2Na+(aq) + 2NO31-(aq)
Sr(NO3)2(aq) + 2Na+(aq) + SO42-(aq) ----> SrSO4(aq) + 2Na+ (aq) + 2NO31-(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> Sr2+(aq) + SO42-(aq) + 2Na+(aq) + 2NO31-(aq)
Sr2+(aq) + NO31-(aq) + Na+(aq) + SO42-(aq) ----> Sr2+(aq) + SO42-(aq) + Na+(aq) + NO31-(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> SrNa2(s) + SO4NO3(aq)
Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> SrSO4(s) + 2Na+(aq) + 2NO31-(aq)
Explanation / Answer
answer : Sr2+(aq) + 2NO31-(aq) + 2Na+(aq) + SO42-(aq) ----> SrSO4(s) + 2Na+(aq) + 2NO31-(aq)
explanation:
complete equation:
Sr(NO3)2 (aq) + Na2SO4 (aq) ---------------------> SrSO4 (s) + 2 NaNO3
net ionic equation:
Sr+2 + SO4-2 -----------------> SrSO4 (s)
so solid is formed in the product . in ionic equation we have to show SrSO4 solid . so last potion is correct