Consider this situation to answer question 1-5. Two balloons are inflated with 2

Question

Consider this situation to answer question 1-5. Two balloons are inflated with 2.0 mol of Helium (MM - 4 gAnol) and 2.0 mol of Argon (MM = 40 g/mol) respectively. The external pressure and temperature are 1.00 atm and 298 K. How will the mass of the Argon balloon compare to the mass of the Helium balloon? 10 times heave 10 times lighter same masses more info needed none of the above How will the volume of the Argon balloon compare to the volume of the Helium balloon? 10 times larger 10 times smaller same volumes more info needed none of the above How will the volume of the Argon balloon compare to the density of the Helium balloon? 10 times higher 10 times lower same densities more info needed none of the above How will the volume of the Argon balloon compare to the volume of the Helium balloon, if both balloons are dipped into liquid nitrogen (T = 77 K)? 10 times larger 10 times smaller same volumes more info needed none of the above How will the density of the Argon balloon compare to the density of the Helium balloon, if both balloons are dipped into liquid nitrogen (T = 77 K)? 10 times higher 10 times lower same densities more info needed none of the above

Explanation / Answer

1)

we know that

mass = moles x molar mass

so

mAr / mHe = 2 x 40 / 2 x 4 = 10

so

A) 10x heavier

2)

we know that

PV = nRT

V = nRT / P

here

n , R , T , P are same for both

so

volumes are same

C) same volumes

3)

we know that

density = mass / volume

volumes are same

so

d Ar / dHe = mAr / mHe

dAr / dHe = 10

so

A) 10x higher

4)

the temperature decrease is same

so

PV = nRT will be same

so

both the volumes will be same

C) same volumes

5) similarly for density

A) 10 x higher

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